Dave Clark Notable

b. September 3, 1962 · Cleveland Indians 1986–1989, Chicago Cubs 1990, 1997, Kansas City Royals 1991, Pittsburgh Pirates 1992–1996, Los Angeles Dodgers 1996, Houston Astros 1998

Dave Clark played for six clubs across 13 seasons as a right fielder, opening with the Cleveland Indians in 1986 and closing with the Houston Astros in 1998. His longest stay was with the Pittsburgh Pirates, from 1992 to 1996.

Across 905 games he batted .264, with 518 hits and 248 runs. He finished with 62 home runs, 81 doubles and 19 stolen bases.

He played 433 games in the outfield, with 661 putouts and 22 errors.

He was born in Tupelo, MS, USA on September 3, 1962. He batted left-handed and threw right-handed.

Batting, season by season

Year	Team	G	AB	R	H	2B	3B	HR	RBI	BB	SO	SB	AVG
1986	CLE	18	58	10	16	1	0	3	9	7	11	1	.276
1987	CLE	29	87	11	18	5	0	3	12	2	24	1	.207
1988	CLE	63	156	11	41	4	1	3	18	17	28	0	.263
1989	CLE	102	253	21	60	12	0	8	29	30	63	0	.237
1990	CHC	84	171	22	47	4	2	5	20	8	40	7	.275
1991	KCR	11	10	1	2	0	0	0	1	1	1	0	.200
1992	PIT	23	33	3	7	0	0	2	7	6	8	0	.212
1993	PIT	110	277	43	75	11	2	11	46	38	58	1	.271
1994	PIT	86	223	37	66	11	1	10	46	22	48	2	.296
1995	PIT	77	196	30	55	6	0	4	24	24	38	3	.281
1996	LAD/PIT	107	226	28	61	12	2	8	36	34	53	2	.270
1997	CHC	102	143	19	43	8	0	5	32	19	34	1	.301
1998	HOU	93	131	12	27	7	0	0	4	14	45	1	.206
Career	—	905	1964	248	518	81	8	62	284	222	451	19	.264

On this day & linked events

1962

Born September 3, 1962

Tupelo, MS, USA

1986

Major-league debut: Dave Clark

Dave Clark made a major-league debut on September 3, 1986.

1998

Final major-league game: Dave Clark

Dave Clark played a final major-league game on September 27, 1998.

Image: Keith Allison, CC BY-SA 2.0