Lee Stevens Notable

b. July 10, 1967 · California Angels 1990–1992, Texas Rangers 1996–1999, Montreal Expos 2000–2002, Cleveland Indians 2002

Lee Stevens played for four clubs across 13 seasons as a first baseman, opening with the California Angels in 1990 and closing with the Cleveland Indians in 2002.

Across 1,012 games he batted .254, with 847 hits and 440 runs. He finished with 144 home runs, 185 doubles and 9 stolen bases.

He played 777 games at first base, with 6,577 putouts and 59 errors. He turned 638 double plays.

He hit three home runs in a game in 1998.

He was born in Kansas City, MO, USA on July 10, 1967. He batted left-handed and threw left-handed.

Batting, season by season

Year	Team	G	AB	R	H	2B	3B	HR	RBI	BB	SO	SB	AVG
1990	CAL	67	248	28	53	10	0	7	32	22	75	1	.214
1991	CAL	18	58	8	17	7	0	0	9	6	12	1	.293
1992	CAL	106	312	25	69	19	0	7	37	29	64	1	.221
1996	TEX	27	78	6	18	2	3	3	12	6	22	0	.231
1997	TEX	137	426	58	128	24	2	21	74	23	83	1	.300
1998	TEX	120	344	52	91	17	4	20	59	31	93	0	.265
1999	TEX	146	517	76	146	31	1	24	81	52	132	2	.282
2000	MON	123	449	60	119	27	2	22	75	48	105	0	.265
2001	MON	152	542	77	133	35	1	25	95	74	157	2	.245
2002	CLE/MON	116	358	50	73	13	2	15	57	54	89	1	.204
Career	—	1012	3332	440	847	185	15	144	531	345	832	9	.254

On this day & linked events

1967

Born July 10, 1967

Kansas City, MO, USA

1990

Major-league debut: Lee Stevens

Lee Stevens made a major-league debut on July 16, 1990.

1998

Lee Stevens's Three-Home-Run Game, 1998

Lee Stevens hit three home runs for the Texas Rangers against the Detroit Tigers on April 13, 1998.

2002

Final major-league game: Lee Stevens

Lee Stevens played a final major-league game on September 27, 2002.