1866
Born February 20, 1866
Chicago, IL, USA
John Pickett Notable
b. February 20, 1866 · Kansas City Cowboys 1889, Philadelphia Athletics 1890, Baltimore Orioles 1892
John Pickett played for three clubs across four seasons as a left fielder, opening with the Kansas City Cowboys in 1889 and closing with the Baltimore Orioles in 1892.
Across 189 games he batted .252, with 189 hits and 115 runs. He finished with 5 home runs, 16 doubles and 21 stolen bases.
He played 147 games at second base, with 412 assists and 84 errors. He turned 57 double plays.
He was born in Chicago, IL, USA on February 20, 1866, and died on July 4, 1922. He batted right-handed and threw right-handed.
Batting, season by season
| Year | Team | G | AB | R | H | 2B | 3B | HR | RBI | BB | SO | SB | AVG |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 1889 | KCC | 53 | 201 | 20 | 45 | 7 | 0 | 0 | 12 | 11 | 21 | 7 | .224 |
| 1890 | PHQ | 100 | 407 | 82 | 114 | 7 | 9 | 4 | 64 | 40 | 17 | 12 | .280 |
| 1892 | BLN | 36 | 141 | 13 | 30 | 2 | 3 | 1 | 12 | 7 | 10 | 2 | .213 |
| Career | — | 189 | 749 | 115 | 189 | 16 | 12 | 5 | 88 | 58 | 48 | 21 | .252 |
On this day & linked events
1922
Died July 4, 1922
Image: Goodwin & Company, public domain