1866
Born November 2, 1866
St. Louis, MO, USA
Frank Genins played for four clubs across 10 seasons as a shortstop, opening with the St. Louis Browns in 1892 and closing with the Cleveland Blues in 1901.
Across 149 games he batted .226, with 116 hits and 75 runs. He finished with 2 home runs, 18 doubles and 32 stolen bases.
He played 70 games in the outfield, with 135 putouts and 10 errors.
He was born in St. Louis, MO, USA on November 2, 1866, and died on September 30, 1922.
| Year | Team | G | AB | R | H | 2B | 3B | HR | RBI | BB | SO | SB | AVG |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 1892 | CIN/STL | 50 | 161 | 17 | 30 | 5 | 0 | 0 | 11 | 13 | 23 | 10 | .186 |
| 1895 | PIT | 73 | 252 | 43 | 63 | 8 | 0 | 2 | 24 | 22 | 14 | 19 | .250 |
| 1901 | CLE | 26 | 101 | 15 | 23 | 5 | 0 | 0 | 9 | 8 | 3 | 3 | .228 |
| Career | — | 149 | 514 | 75 | 116 | 18 | 0 | 2 | 44 | 43 | 40 | 32 | .226 |
St. Louis, MO, USA
Frank Genins made a major-league debut on May 11, 1892.
Frank Genins played a final major-league game on May 23, 1901.
Image: Goodwin & Company, public domain