1958
Born November 5, 1958
Menomonie, WI, USA
Tom Wiedenbauer played 1979 for the Houston Astros as a left fielder.
Across 4 games he batted .667, with 4 hits and 0 runs. He finished with 1 double.
He was born in Menomonie, WI, USA on November 5, 1958. He batted right-handed and threw right-handed.
Batting, season by season
| Year | Team | G | AB | R | H | 2B | 3B | HR | RBI | BB | SO | SB | AVG |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 1979 | HOU | 4 | 6 | 0 | 4 | 1 | 0 | 0 | 2 | 0 | 2 | 0 | .667 |
| Career | — | 4 | 6 | 0 | 4 | 1 | 0 | 0 | 2 | 0 | 2 | 0 | .667 |
On this day & linked events
Image: Keith Allison, CC BY-SA 2.0