1891
Born September 21, 1891
Swiftwater, MS, USA
Pete Shields played 1915 for the Cleveland Indians as a first baseman.
Across 23 games he batted .208, with 15 hits and 4 runs. He finished with 6 doubles and 3 stolen bases.
He played 23 games at first base, with 208 putouts and 6 errors. He turned 5 double plays.
He was born in Swiftwater, MS, USA on September 21, 1891, and died on February 11, 1961. He batted right-handed and threw right-handed.
| Year | Team | G | AB | R | H | 2B | 3B | HR | RBI | BB | SO | SB | AVG |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 1915 | CLE | 23 | 72 | 4 | 15 | 6 | 0 | 0 | 6 | 4 | 14 | 3 | .208 |
| Career | — | 23 | 72 | 4 | 15 | 6 | 0 | 0 | 6 | 4 | 14 | 3 | .208 |
Swiftwater, MS, USA
Image: Bain News Service, public domain