1876
Born August 24, 1876
Philadelphia, PA, USA
John Brown played 1897 for the Brooklyn Bridegrooms as a pitcher.
He went 0 and 1 with a 7.20 earned run average, pitching 5 innings in 1 game. Across 1 game he batted .500, with 1 hit and 0 runs.
He was born in Philadelphia, PA, USA on August 24, 1876, and died on July 18, 1908.
| Year | Team | G | AB | R | H | 2B | 3B | HR | RBI | BB | SO | SB | AVG |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 1897 | BRO | 1 | 2 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | .500 |
| Career | — | 1 | 2 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | .500 |
| Year | Team | W | L | G | GS | SV | IP | H | ER | BB | SO | ERA |
|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 1897 | BRO | 0 | 1 | 1 | 1 | 0 | 5.0 | 7 | 4 | 4 | 0 | 7.20 |
| Career | — | 0 | 1 | 1 | 1 | 0 | 5.0 | 7 | 4 | 4 | 0 | 7.20 |
Philadelphia, PA, USA