1900
Born April 6, 1900
Petersburg, IN, USA
Joe Wyatt played 1924 for the Cleveland Indians as a right fielder.
Across 4 games he batted .167, with 2 hits and 1 run.
He was born in Petersburg, IN, USA on April 6, 1900, and died on December 5, 1970. He batted right-handed and threw right-handed.
| Year | Team | G | AB | R | H | 2B | 3B | HR | RBI | BB | SO | SB | AVG |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 1924 | CLE | 4 | 12 | 1 | 2 | 0 | 0 | 0 | 1 | 2 | 1 | 0 | .167 |
| Career | — | 4 | 12 | 1 | 2 | 0 | 0 | 0 | 1 | 2 | 1 | 0 | .167 |
Petersburg, IN, USA