1893
Born August 27, 1893
Newberg, OR, USA
Howie Haworth played 1915 for the Cleveland Indians as a catcher.
Across 7 games he batted .143, with 1 hit and 0 runs.
He was born in Newberg, OR, USA on August 27, 1893, and died on January 28, 1953. He batted left-handed and threw right-handed.
| Year | Team | G | AB | R | H | 2B | 3B | HR | RBI | BB | SO | SB | AVG |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 1915 | CLE | 7 | 7 | 0 | 1 | 0 | 0 | 0 | 1 | 2 | 2 | 0 | .143 |
| Career | — | 7 | 7 | 0 | 1 | 0 | 0 | 0 | 1 | 2 | 2 | 0 | .143 |
Newberg, OR, USA
Image: Unknown author Unknown, public domain