1881
Born July 5, 1881
St. Joseph, MO, USA
Harry Aubrey Notable
b. July 5, 1881 · Boston Beaneaters 1903
Harry Aubrey played 1903 for the Boston Beaneaters as a shortstop.
Across 96 games he batted .212, with 69 hits and 26 runs. He finished with 8 doubles and 7 stolen bases.
He played 94 games at shortstop, with 301 assists and 74 errors. He turned 20 double plays.
He was born in St. Joseph, MO, USA on July 5, 1881, and died on September 18, 1953. He batted right-handed and threw right-handed.
Batting, season by season
| Year | Team | G | AB | R | H | 2B | 3B | HR | RBI | BB | SO | SB | AVG |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 1903 | BSN | 96 | 325 | 26 | 69 | 8 | 2 | 0 | 27 | 18 | 36 | 7 | .212 |
| Career | — | 96 | 325 | 26 | 69 | 8 | 2 | 0 | 27 | 18 | 36 | 7 | .212 |
On this day & linked events
1953