1943
Born August 20, 1943
Washington, DC, USA
Hal Kurtz played 1968 for the Cleveland Indians as a pitcher.
He went 1 and 0 with a 5.21 earned run average, pitching 38 innings in 28 games. He struck out 16. Across 30 games he batted .000, with 0 hits and 0 runs.
He was born in Washington, DC, USA on August 20, 1943. He batted right-handed and threw right-handed.
| Year | Team | G | AB | R | H | 2B | 3B | HR | RBI | BB | SO | SB | AVG |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 1968 | CLE | 30 | 4 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | .000 |
| Career | — | 30 | 4 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | .000 |
| Year | Team | W | L | G | GS | SV | IP | H | ER | BB | SO | ERA |
|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 1968 | CLE | 1 | 0 | 28 | 0 | 1 | 38.0 | 37 | 22 | 15 | 16 | 5.21 |
| Career | — | 1 | 0 | 28 | 0 | 1 | 38.0 | 37 | 22 | 15 | 16 | 5.21 |
Washington, DC, USA