1884
Born November 11, 1884
Libby, MN, USA
Frank Jude played 1906 for the Cincinnati Reds as a right fielder.
Across 80 games he batted .208, with 64 hits and 31 runs. He finished with 1 home run, 6 doubles and 7 stolen bases.
He played 80 games in the outfield, with 95 putouts and 4 errors.
He was born in Libby, MN, USA on November 11, 1884, and died on May 4, 1961. He batted right-handed and threw right-handed.
| Year | Team | G | AB | R | H | 2B | 3B | HR | RBI | BB | SO | SB | AVG |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 1906 | CIN | 80 | 308 | 31 | 64 | 6 | 4 | 1 | 31 | 16 | 35 | 7 | .208 |
| Career | — | 80 | 308 | 31 | 64 | 6 | 4 | 1 | 31 | 16 | 35 | 7 | .208 |
Libby, MN, USA
Image: Unknown author Unknown, public domain