1973
Born January 30, 1973
Mobile, AL, USA
Bob Henley played 1998 for the Montreal Expos as a catcher.
Across 41 games he batted .304, with 35 hits and 16 runs. He finished with 3 home runs, 8 doubles and 3 stolen bases.
He played 35 games behind the plate, with 189 putouts and 1 error. He turned 1 double play.
He was born in Mobile, AL, USA on January 30, 1973. He batted right-handed and threw right-handed.
| Year | Team | G | AB | R | H | 2B | 3B | HR | RBI | BB | SO | SB | AVG |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 1998 | MON | 41 | 115 | 16 | 35 | 8 | 1 | 3 | 18 | 11 | 26 | 3 | .304 |
| Career | — | 41 | 115 | 16 | 35 | 8 | 1 | 3 | 18 | 11 | 26 | 3 | .304 |
Mobile, AL, USA