1876
Born June 24, 1876
Los Angeles, CA, USA
Bill Hanlon played 1903 for the Chicago Cubs as a first baseman.
Across 8 games he batted .095, with 2 hits and 4 runs. He finished with 1 stolen base.
He was born in Los Angeles, CA, USA on June 24, 1876, and died on November 23, 1905.
| Year | Team | G | AB | R | H | 2B | 3B | HR | RBI | BB | SO | SB | AVG |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 1903 | CHC | 8 | 21 | 4 | 2 | 0 | 0 | 0 | 2 | 6 | 6 | 1 | .095 |
| Career | — | 8 | 21 | 4 | 2 | 0 | 0 | 0 | 2 | 6 | 6 | 1 | .095 |
Los Angeles, CA, USA