1979
Born July 4, 1979
Havana, La Habana, Cuba
Amauri Sanit played 2011 for the New York Yankees as a pitcher.
He went 0 and 0 with a 12.86 earned run average, pitching 7 innings in 4 games. He struck out 4.
He was born in Havana, La Habana, Cuba on July 4, 1979. He batted right-handed and threw right-handed.
Batting, season by season
| Year | Team | G | AB | R | H | 2B | 3B | HR | RBI | BB | SO | SB | AVG |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 2011 | NYY | 4 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | — |
| Career | — | 4 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | — |
Pitching, season by season
| Year | Team | W | L | G | GS | SV | IP | H | ER | BB | SO | ERA |
|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 2011 | NYY | 0 | 0 | 4 | 0 | 0 | 7.0 | 12 | 10 | 3 | 4 | 12.86 |
| Career | — | 0 | 0 | 4 | 0 | 0 | 7.0 | 12 | 10 | 3 | 4 | 12.86 |
On this day & linked events
Image: Presidencia de la República Mexicana on Flickr, CC BY 2.0