1886
Born October 31, 1886
Laurinburg, NC, USA
Alex Malloy played 1910 for the St. Louis Browns as a pitcher.
He went 0 and 6 with a 2.56 earned run average, pitching 52.7 innings in 7 games. He struck out 27. Across 7 games he batted .062, with 1 hit and 0 runs.
He was born in Laurinburg, NC, USA on October 31, 1886, and died on March 1, 1961. He batted right-handed and threw right-handed.
| Year | Team | G | AB | R | H | 2B | 3B | HR | RBI | BB | SO | SB | AVG |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 1910 | SLB | 7 | 16 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | 3 | 0 | .063 |
| Career | — | 7 | 16 | 0 | 1 | 0 | 0 | 0 | 0 | 1 | 3 | 0 | .063 |
| Year | Team | W | L | G | GS | SV | IP | H | ER | BB | SO | ERA |
|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 1910 | SLB | 0 | 6 | 7 | 6 | 0 | 52.2 | 47 | 15 | 17 | 27 | 2.56 |
| Career | — | 0 | 6 | 7 | 6 | 0 | 52.2 | 47 | 15 | 17 | 27 | 2.56 |
Laurinburg, NC, USA
Image: Old Mill, public domain