1868
Born February 13, 1868
Hartford, CT, USA
Timothy Sheehan Notable
b. February 13, 1868 · St. Louis Browns 1895–1896
Timothy Sheehan played 1895 to 1896 for the St. Louis Browns as a right fielder.
Across 58 games he batted .302, with 60 hits and 24 runs. He finished with 1 home run, 3 doubles and 7 stolen bases.
He played 47 games in the outfield, with 66 putouts and 4 errors.
He was born in Hartford, CT, USA on February 13, 1868, and died on October 21, 1923. He batted left-handed and threw right-handed.
Batting, season by season
| Year | Team | G | AB | R | H | 2B | 3B | HR | RBI | BB | SO | SB | AVG |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 1895 | STL | 52 | 180 | 24 | 57 | 3 | 6 | 1 | 18 | 20 | 6 | 7 | .317 |
| 1896 | STL | 6 | 19 | 0 | 3 | 0 | 0 | 0 | 1 | 4 | 0 | 0 | .158 |
| Career | — | 58 | 199 | 24 | 60 | 3 | 6 | 1 | 19 | 24 | 6 | 7 | .302 |
On this day & linked events
1923