1893
Born June 25, 1893
Everett, PA, USA
Earl Howard played 1918 for the St. Louis Cardinals as a pitcher.
He went 0 and 0 with a 0.00 earned run average, pitching 2 innings in 1 game.
He was born in Everett, PA, USA on June 25, 1893, and died on April 5, 1937. He batted right-handed and threw right-handed.
| Year | Team | G | AB | R | H | 2B | 3B | HR | RBI | BB | SO | SB | AVG |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 1918 | STL | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | — |
| Career | — | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | — |
| Year | Team | W | L | G | GS | SV | IP | H | ER | BB | SO | ERA |
|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 1918 | STL | 0 | 0 | 1 | 0 | 0 | 2.0 | 0 | 0 | 2 | 0 | 0.00 |
| Career | — | 0 | 0 | 1 | 0 | 0 | 2.0 | 0 | 0 | 2 | 0 | 0.00 |
Everett, PA, USA