1941
Born December 5, 1941
Florin, PA, USA
Bob Sprout played 1961 for the Los Angeles Angels as a pitcher.
He went 0 and 0 with a 4.50 earned run average, pitching 4 innings in 1 game. He struck out 2.
He was born in Florin, PA, USA on December 5, 1941. He batted left-handed and threw left-handed.
Batting, season by season
| Year | Team | G | AB | R | H | 2B | 3B | HR | RBI | BB | SO | SB | AVG |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 1961 | LAA | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | — |
| Career | — | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | — |
Pitching, season by season
| Year | Team | W | L | G | GS | SV | IP | H | ER | BB | SO | ERA |
|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 1961 | LAA | 0 | 0 | 1 | 1 | 0 | 4.0 | 4 | 2 | 3 | 2 | 4.50 |
| Career | — | 0 | 0 | 1 | 1 | 0 | 4.0 | 4 | 2 | 3 | 2 | 4.50 |