1884
Born June 16, 1884
Philadelphia, PA, USA
Bob Peterson Notable
b. June 16, 1884 · Boston Americans 1906–1907
Bob Peterson played 1906 to 1907 for the Boston Americans as a catcher.
Across 43 games he batted .191, with 25 hits and 11 runs. He finished with 1 home run, 1 double and 1 stolen base.
He played 34 games behind the plate, with 135 putouts and 18 errors. He turned 1 double plays.
He was born in Philadelphia, PA, USA on June 16, 1884, and died on November 27, 1962. He batted right-handed and threw right-handed.
Batting, season by season
| Year | Team | G | AB | R | H | 2B | 3B | HR | RBI | BB | SO | SB | AVG |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 1906 | BOS | 39 | 118 | 10 | 24 | 1 | 1 | 1 | 9 | 11 | 23 | 1 | .203 |
| 1907 | BOS | 4 | 13 | 1 | 1 | 0 | 0 | 0 | 0 | 0 | 2 | 0 | .077 |
| Career | — | 43 | 131 | 11 | 25 | 1 | 1 | 1 | 9 | 11 | 25 | 1 | .191 |
On this day & linked events
1962